Prepjunk - Recent questions and answers in Interview

Answered: In c,if you pass an array as an argument to a function,what actuallay gets passed ?

Fri, 30 Mar 2012 16:28:15 +0000

Base address of an array.

Answered: what is the result of 16>>2 ?

Fri, 30 Mar 2012 16:23:58 +0000

The answer is 4

Answered: Write program to find 2-nd largest element in an array with single loop.

Thu, 29 Mar 2012 17:17:19 +0000

Function

//program to find second largest element
            int secondMaxElement(int a[], int len) 
    {
                int max = INT_MIN, secondMax = INT_MIN, i;
                for(i = 0; i < len; i++) {
                    if(a[i] > max) {
                        secondMax = max;
                        max = a[i];
                    }
                    else if(a[i] > secondMax && a[i] < max)
                        secondMax = a[i];
                }
                return secondMax;
            }

Answered: Substitute digits for the letters to make the following subtraction problem true.

Thu, 29 Mar 2012 14:47:48 +0000

One of the simplest brain teaser as there are total 26 possible answers.
It is obvious that S=C+1. Since A-S=S, it is clear that A=2 * S or 2 * s-10. Also, L
and X are interchangeable.
SANTA - CLAUS = XMAS

24034 - 16492 = 7542
24034 - 17492 = 6542
24074 - 15432 = 8642
24074 - 18432 = 5642
24534 - 16492 = 8042
24534 - 18492 = 6042
24794 - 16452 = 8342
24794 - 18452 = 6342
24804 - 15462 = 9342
24804 - 19462 = 5342
24974 - 16432 = 8542
24974 - 18432 = 6542
36806 - 27643 = 9163
36806 - 29643 = 7163
36156 - 27693 = 8463
36156 - 28693 = 7463
62132 - 54206 = 7926
62132 - 57206 = 4926
62172 - 53246 = 8926
62172 - 58246 = 3926
62402 - 53276 = 9126
62402 - 59276 = 3126
62712 - 53286 = 9426
62712 - 59286 = 3426
62932 - 58206 = 4726
62932 - 54206 = 8726

Answered: Yesterday in a party, I asked Mr. Shah his birthday. With a mischievous glint in

Thu, 29 Mar 2012 14:47:01 +0000

Mr. Shah's date of birth is 31 December, 1915
Today is 1 January, 2000. The day before yesterday was 30 December, 1999
and Mr. Shah was 83 on that day. Today i.e. 1 January, 2000 - he is 84. On 31
December 2000, he will be 85 and next year i.e. 31 December, 2001 - he will be
86. Hence, the date of birth is 31 December, 1915.
Many people do think of Leap year and date of birth as 29th February as 2000 is
the Leap year and there is difference of 3 years in Mr. Shah's age. But that is not
the answer.

Answered: Mr. D'souza has bought four cars - Merc, Honda, Ford, Zen - as presents for his

Thu, 29 Mar 2012 14:46:22 +0000

Let's put given 9 information in a table. The person in Bold Font will not get the
corresponding car unless the persons in Normal Font get the corresponding cars.
Also, the person will Italics will get the remaining car.
Merc Honda Ford Zen
1 Barry Alan Denzil Carl
2 Alan Denzil Barry Carl
3 Barry Alan Carl Denzil
4 Alan Barry Denzil Carl
5 Barry Carl Denzil Alan
6 Carl Barry Denzil Alan
7 Denzil Barry Alan Carl
8 Carl Denzil Alan Barry
9 Carl Denzil ? ?
Now, let's assume that Alan gets the Merc. Then from (4), Barry gets the Honda,
Denzil gets the Ford and Carl gets the Zen. But from (7), Carl will not get the Zen
unless Barry gets the Honda and Alan gets the Ford. Thus, it contradicts the
original assumption. Hence, Alan will not get the Merc.
Let's assume that Alan gets the Honda. Then from (1), Barry gets the Merc,
Denzil gets the Ford and Carl gets the Zen. But from (5) or from (7), it contradicts
the original assumption. Hence, Alan will not get the Honda.
Let's assume that Alan gets the Ford. Then from (8), Carl gets the Merc, Denzil
gets the Ford and Barry gets the Zen - which does not contradict any of the
statement.
Similaly, you can assume that Alan gets the Zen. (which is contradictory to (9))
Hence, Alan gets the Ford, Barry gets the Zen, Carl gets the Merc and Denzil
gets the Honda.

Answered: A positive integer that, when added to 1000 gives a sum which is greater than when multiplied by 1000. Find the positive integer

Thu, 29 Mar 2012 14:45:50 +0000

The positive integer is 1.
Sum of 1 and 1000 = 1 + 1000 = 1001
Multiplication of 1 and 1000 = 1 * 1000 = 1000
Thus, sum of 1 and 1000 is greater than the multiplication of 1 and 1000.

Answered: • A is the father of two children - B and D who are of different sexes. • C is B's spouse.

Thu, 29 Mar 2012 14:45:25 +0000

There are 7 females and 6 males.
Assume that there are four sexes - male, female, X and Y. Prepare the following
tree based on the data given :
sister

L(m) - H(f) -------------------- M(f) - A(m)
| |
| |
E(x) - I(y) D(x) B(y) -
C(x)
| |
| |
J(y) K(y) F(y)
G(x)

It is clear that there are altogether 13 persons - 2 males, 2 females, 4 Xs and 5 Ys.
It is given that there are more number of females than male. Hence, all Y must represent female. Thus, there are 7 females and 6 males.

Answered: Father's age is three years more than three times the son's age. After three

Thu, 29 Mar 2012 14:44:42 +0000

Let son's present age is X years.
Hence, father's present age is (3X + 3) years.
After 3 years, son's age will be (X + 3) years.
and father's age will be (3X + 6) years.
But given that after 3 years father's age will be ten years more than twice the
son's age.
(3X + 6) = 2 * (X + 3) + 10
3X + 6 = 2X + 16
X = 10
Therefore, father's present age is 33 years.

Answered: In training for a competition, you find that swimming downstream (with the

Thu, 29 Mar 2012 14:44:14 +0000

You are able to swim downstream at 3 miles an hour, & upstream at 2 miles an
hour. There is a difference of 1 mile an hour, which is the river helping you in 1
direction, & slowing you in the other direction.
Average the 2 rates, & you have the rate that you can swim in still water, which is
2.5 miles an hour.
You can thus swim a mile in still water in 24 minutes.

Answered: Annie, Bunnie, Candy and Dina visited Edy on 14th February.

Thu, 29 Mar 2012 14:43:33 +0000

Bunnie (9:00AM) - Dina (11:00AM) - Annie (8:00PM) - Candy (10:00PM)
From the given data, it is clear that at least one female visited Edy in the morning
and at least one female visited Edy in the evening. Also, from (4), Annie did not
visit Edy first. It means that Annie visited Edy at 8:00 PM
From (3), Bunnie must have visited Edy at 9:00 AM. Also, either Candy or Dina
or both visited Edy in the morning.
But from (2), only Dina must have visited Edy in the morning at 11:00 AM and
hence, Candy visited Edy at 10:00 PM.
The order of visits must be:
Bunnie (9:00AM) - Dina (11:00AM) - Annie (8:00PM) - Candy (10:00PM)

Answered: An orange colored glass has Orange juice and white colored glass has Apple

Thu, 29 Mar 2012 14:43:03 +0000

The two quantities are equal.
Solve it by taking example. Let's assume that both glasses contain 450 ml of
juice each.
Now, 50ml of the orange juice is taken and poured into the White glass. Hence,
orange colored glass contains 400 ml of Orange juice and white glass contains
450 ml of Apple juice and 50 ml of Orange juice i.e. total of 500 ml from white
glass contains 450 ml of Apple juice and 50 ml of Orange juice. It means that
every 50 ml from white glass contains 45 ml of Apple juice and 5 ml of
Orange juice.
Similary, 50 ml of juice from white glass is poured into orange glass. Now this 50
ml is not a pure apple juice. It contains 45 ml of Apple juice and 5 ml of Orange
juice.
Hence, Orange glass contains 405 ml of Orange juice and 45 ml of Apple juice.
Similary, white glass contains 405 ml of Apple juice and 45 ml of Orange juice.
Orange Glass White Glass
Orange
Juice
Apple
Juice
Orange
Juice
Apple
Juice
Initially 450 ml 0 ml 0 ml 450 ml
50 ml from Orange Glass is
poured into White Glass 400 ml 0 ml 50 ml 450 ml
50 ml from White Glass is poured
into Orange Glass 405 ml 45 ml 45 ml 405 ml
Now it is clear that the amount of apple juice in the orange glass and the amount
of orange juice in the white glass are the same.
P.S. Here we assumed 450 ml as initial quantity in both the glasses just for

simplicity. You can try the same by assuming any other number. But the answer
is the same.

Answered: Four men - Abraham, Bobby, Clinton and Denial - are standing in a straight

Thu, 29 Mar 2012 14:39:50 +0000

Clinton is fair, handsome and unscarred.
From (2), both the men standing next to Abraham are not fair. Also, exactly one
man is fair, handsom and unscarred. Hence, there are two cases:
Case 1 :: ? (N, ?, ?) : Abraham (Y, Y, N) : ? (N, ?, ?) : ? (?, ?, ?)
Case 2 :: ? (N, ?, ?) : Abraham (?, ?, ?) : ? (N, ?, ?) : ? (Y, Y, N)
Note the representation - Name (Fair, Handsome, Scarred). "Y" stands for Yes
and "N" stabds for No. Abraham (Y, Y, N) means Abraham is Fair, Handsome
and Unscarred.
It is clear that either Abraham or the man at the extreme right is fair, handsome
and unscarred.
From (4), it is deduced that Clinton is standing next to unscarred man and each
of the other men standing next to exactly one scarred man.
Case 1 :: Clinton (N, ?, N) : Abraham (Y, Y, N) : ? (N, ?, Y) : ? (?, ?, Y)
Case 2 :: ? (N, ?, Y) : Abraham (?, ?, Y) : ? (N, ?, N) : Clinton (Y, Y, N)
From (3), Bobby is the only man standing next to exactly one handsome man.
But in Case 1, Clinton is standing next to exactly one handsome man. Hence,
Case 1 is not possible and Case 2 is the correct one.
Case 2 :: ? (N, ?, Y) : Abraham (?, ?, Y) : ? (N, ?, N) : Clinton (Y, Y, N)
Again from (3) and (4), there are 2 possibilities as shown below.
Case 2a :: Denial (N, N, Y) : Abraham (?, N, Y) : Bobby (N, N, N) : Clinton (Y, Y,
N)
Case 2b :: Bobby (N, N, Y) : Abraham (?, Y, Y) : Denial (N, N, N) : Clinton (Y, Y,
N)
Thus, Clinton is fair, handsome and unscarred. Also, Abraham may be either fair
or not fair.

Answered: The secret agent X emailed a code word to his head office. They are "AIM DUE

Thu, 29 Mar 2012 14:39:08 +0000

The code word is TIE.
If you were told any one character of MOD, then you would not be able to
determine whether the number of vowels are one or two. e.g. if you were told M,
there are two words with M - AIM with 2 vowels and MOD with 1 vowel. So you
would not be able to say the number of vowels. Same arguments can be given
for characters O and D.
Hence, the word with any one of M, O or D is not a code word i.e. AIM, DUE,
OAT and MOD are not the code word. Thus, TIE is the code word.
T : two words - TIE and OAT, both with 2 vowels
I : two words - TIE and AIM, both with 2 vowels
E : two words - TIE and DUE, both with 2 vowels.

Answered: Eleven boys and girls wait to take their seats in the same row in a movie theater.

Thu, 29 Mar 2012 14:38:27 +0000

There are 1024 different ways.
This is the type of Brain Teaser that can be solved using the method of induction.
If there is just a one person and one seat, that person has only one option.
If there are two persons and two seats, it can be accomplished in 2 different
ways.
If there are three persons and three seats, it can be accomplished in 4 different
ways. Remember that no person can take a seat that separates him/her from at
least one other person.

Similarly, four persons and four seats produce 8 different ways. And five persons
with five seats produce 16 different ways.
It can be seen that with each additional person and seat, the different ways
increase by the power of two. For six persons with six seats, there are 32
different ways.
For any number N, the different possible ways are 2(N-1)
Thus, for 11 persons and 11 seats, total different ways are 210 i.e. 1024

Answered: Five students - Akash, Chintan, Jignesh, Mukund and Venky - appeared for an

Thu, 29 Mar 2012 14:37:48 +0000

The correct answers are b, a, True, False and False. Also, the scores are
Jignesh (0), Akash (1), Chintan (2), Venky (3) and Mukund (4).
As no two students got the same number of correct answers, the total number of
correct answers must be either 15 (1+2+3+4+5) or 10 (0+1+2+3+4).
Let's find out the maximum number of correct answers possible from the answers given by them.
For Question I = 2 (b or c)
For Question II = 2 (b or c)
For Question III = 4 (True)
For Question IV = 4 (True)
For Question V = 3 (True)
Thus, the maximum number of correct answers possible are 15 (2+2+4+4+3)
which means that Akash would have given all correct answers as only he answered True for questions III, IV and V. But then Chintan and Jignesh would
have exactly 3 correct answers. And also, Mukund and Venky would have 2 correct answers. So no one got all five correct. One can also arrive at this conclusion by trial-and-error, but that would be bit lengthy.
Now, it is clear that total number of correct answers are 10 (0+1+2+3+4).
Questions III and IV both can not be False. If so, total number of correct answers would not be 10. So the student who got all wrong can not be Chintan, Akash and Mukund.
If Venky got all wrong, then Chintan, Jignesh and Mukund each would have atleast 2 correct answers. It means that Akash would have to be the student with only one correct answer and the correct answers for questions I and II would be a and a respectively. But then the total number of correct answers would be 1 (a) + 1 (a) + 1 (False) + 4 (True) + 2 (Flase) = 9.
Thus, Jignesh is the student with all wrong answers. The correct answers are b, a, True, False and False. Also, the scores are Jignesh (0), Akash (1), Chintan (2), Venky (3) and Mukund (4).

Answered: How long would it take you to count 1 billion orally if you could count 200 every

Thu, 29 Mar 2012 14:36:57 +0000

9 Years, 187 Days, 5 Hours, 20 minutes
As you can count 200 per minute, to count 1 billion you require
= 1,000,000,000/200 minutes
= 5,000,000 minutes
= 83,333.3333 hours
= 3,472.2222 days
= 9.512937 years
= 9 Years, 187 Days, 5 Hours, 20 minutes
Note that a day off every four year will be a Leap day. Hence, no need to
consider leap year.

Answered: At the entrance to a members club stands a stranger seeking admission. A friend told him that it's easy to get in.

Thu, 29 Mar 2012 14:36:30 +0000

The correct answer was "Four".
The answer is the number of letters in the word spoken by the door warden.
"Twelve" contains "Six" letters i.e. T, W, E, L, V, E
"Six" contains "Three" letters i.e. S, I, X
Similarly, "Four" contains "Four" letters i.e. F, O, U, R
There is a perfect sphere of diameter 40 cms. resting up against a perfectly
straight wall and a perfectly straight floor i.e. the wall and the floor make a perfect
right angle.

Answered: If one person sends the e-mail to two friends, asking each of them to copy the

Thu, 29 Mar 2012 14:35:54 +0000

2147483646
First person sent the mail to 2 persons. Those 2 sent the mail to 2 persons each,
total 4 persons. Now, those 4 person sent mail to total 8 persons, then 8 to 16
persons, 16 to 32 persons and so on.... Hence, it a series of 2, 4, 8, 16, 32 upto
30 numbers
It is a Geometric series with common ratio 2 and first number is also 2.
Summation of such series is given by A * (Rn - 1) / (R - 1) where
A = First term
R = Common Ratio
n = total numbers
So total number of times mail sent by the time it did 30 sets
= 2 * (230 - 1) / (2 - 1)
= 2 * (1073741824 - 1)
= 2 * 1073741823
= 2147483646

Answered: If you added together the number of 2's in each of the following sets of numbers, which set would contain the most 2's: 1-333, 334-666, or 667-999?

Thu, 29 Mar 2012 14:35:28 +0000

1-333
The reason why is because 200-299 each begins with a 2!

Answered: Five horses ran in the race.

Thu, 29 Mar 2012 14:35:06 +0000

It's simple.
Let's find the possible places horses can finish. Possibilities are:
Sikandar - 2,3,4 (not 5th as Mughal Glory came one place after him)
Star - 2,3,4
Mughal Glory - 3,4,5
Zozo - 1,3 (not 4th & 5th as Rangila is two place after him)

Rangila - 3,5
So the result is:
1 Zozo
2 Star
3 Rangila
4 Sikandar
5 Mughal Glory

Answered: How many squares are there in a 5 inch by 5 inch square grid? Note that the grid

Thu, 29 Mar 2012 14:34:35 +0000

There are 55 squares in a 5 by 5 grid.
There are 25 squares of one grid.
There are 16 squares of four grids i.e. 2 by 2
There are 9 squares of nine grids i.e. 3 by 3
There are 4 squares of sixteen grids i.e. 4 by 4
There is 1 square of twenty-five girds i.e. 5 by 5
Hence, there are total 25 + 16 + 9 + 4 + 1 = 55 squares.
You must have noticed one thing that total number squares possible of each size
is always a perfact square i.e. 25, 16, 9, 4, 1
For a grid of N by N, the possible number of squares are
= N2 + (N - 1)2 + (N - 2)2 + (N - 3)2 + ......... + 32 + 22 + 12
For 1 by 1 grid, total squares = 12 = 1
For 2 by 2 grid, total squares = 22 + 12 = 5
For 3 by 3 grid, total squares = 32 + 22 + 12 = 14
For 4 by 4 grid, total squares = 42 + 32 + 22 + 12 = 30
For 5 by 5 grid, total squares = 52 + 42 + 32 + 22 + 12 = 55

Answered: You have 13 balls which all look identical. All the balls are the same weight

Thu, 29 Mar 2012 14:34:04 +0000

It is always possible to find odd ball in 3 weighings and in most of the cases it is
possible to tell whether the odd ball is heavier or lighter. Only in one case, it is
not possible to tell the odd ball is whether heavier or lighter.
1. Take 8 balls and weigh 4 against 4.
o If both are not equal, goto step 2
o If both are equal, goto step 3
2. One of these 8 balls is the odd one. Name the balls on heavier side of the
scale as H1, H2, H3 and H4. Similarly, name the balls on the lighter side
of the scale as L1, L2, L3 and L4. Either one of H's is heavier or one of L's
is lighter. Weigh (H1, H2, L1) against (H3, H4, X) where X is one ball from
the remaining 5 balls in intial weighing.
o If both are equal, one of L2, L3, L4 is lighter. Weigh L2 against L3.

Answered: A drinks machine offers three selections - Tea, Coffee or Random (Either tea or Coffee) but the machine has

Thu, 29 Mar 2012 14:33:32 +0000

You have to put just 50p.

Put 50p and push the button for Random. There are only 2 possibilities. It will
give either Tea or Coffee.
• If it gives Tea, then the button named Random is for Tea. The button
named Coffee is for Random selection. And the button named Tea is for
Coffee.
• If it gives Coffee, then the button named Random is for Coffee. The button
named Tea is for Random selection. And the button named Coffee is for
Tea.
Thus, you can make out which button is for what by putting just 50p and pressing
Random selection first.

Answered: A fly is flying between two trains, each travelling towards each other on the same

Thu, 29 Mar 2012 14:32:11 +0000

Initially, the trains were 240 km apart.
The fly is flying at the speed of 90 km/h and covers 180 km. Hence, the fly flies for 2 hours after trains started.
It's obvious that trains met 2 hours after they started travelling towards each other. Also, trains were travelling at the speed of 60 km/h. So, each train traveled 120 km before they met.
Hence, the trains were 240 km apart initially.
What is the minimum number of numbers needed to form every number from 1 to 7,000? Example: To form 4884, you would need 2 4s & 2 8s. 4822 requires a 4,
a 8, & 2 2s, but you would not count the numbers again that you had already counted from making 4884.

Answered: Three Gold (G) coins, three Silver (S) coins and three Copper (C) coins are

Thu, 29 Mar 2012 14:31:31 +0000

Minimum number of moves are 8.
Move Order of Coins

0 G S C G S C G S C
1 G S G S C G S C C
2 G S C G S C C S G
3 G S C G S C C S G
4 G S C C S G S C G
5 G S C C S C S G G
6 G S C C C S S G G
7 C C C S S G G S G


8 C C C S S S G G G

Answered: Three convicts are brought into the warden's office. He says he can parole

Thu, 29 Mar 2012 14:30:43 +0000

The color of blind man's hat is Red.
It is sure that the first man saw either both Red hats or one White
hat and one Red hat. There are 6 such possibilities:
1) R R R
2) R R W
3) R W R
4) W R R
5) W R W
6) W W R
In all above possibilities, the first man won't be sure of the color of his hat.
Now, the second man knows that the first man saw either both Red hats or one White hat and one Red hat. And, he also knows that its one of the above 6 possibilities. (like we know ;)) But he says, "I don't know". That means that (2) and (5) are not the possibilities as in either case he would be sure of the color of his hat (Red) by just
looking at the third man's color of hat (White).
Now, the blind man knows that there are just 4 possibilities - (1),
(3), (4), (6) - and in all, the color of his hat is Red.

Answered: Pinto says, "The horse is not Black."

Thu, 29 Mar 2012 14:28:30 +0000

The color of the horse can be any color other than Black and Brown.
If the color of the horse is Black - all are lying.
If the color of the horse is Brown - all are telling truth.
Thus, the horse is neither Black nor Brown.
If the color of the horse is Grey - Pinto and Sandy are telling truth whereas Andy
is lying.
If the color of the horse is other than Black, Brown and Grey - Pinto is telling truth
whereas Sandy and Andy are lying.
You must have noticed that for the given conditions, Pinto is always telling truth
whereas Andy is always lying

Answered: Suppose five bales of hay are weighed two at a time in all possible ways. The

Thu, 29 Mar 2012 14:27:51 +0000

They weigh 54, 56, 58, 59, 62 pounds.
Let's assume that the weight of five bales are B1, B2, B3, B4 and B5 pounds
respectively. Also, B1 <= B2 <= B3 <= B4 <= B5
It is given that five bales of hay are weighed two at a time in all possible ways. It
means that each of the bale is weighted four times.
Thus,
4 * (B1 + B2 + B3 + B4 + B5) = (110 + 112 + 113 + 114 + 115 + 116 + 117 + 118 +
120 + 121)
4 * (B1 + B2 + B3 + B4 + B5) = 1156
(B1 + B2 + B3 + B4 + B5) = 289 pounds
Now, B1 and B2 must add to 110 as they are the lightest one.
B1 + B2 = 110
Similarly, B4 and B5 must add to 121 as they are the heaviest one.
B4 + B5 = 121
From above three equation, we get B3 = 58 pounds
Also, it is obvious that B1 and B3 will add to 112 - the next possible higher value.
Similarly, B3 and B5 will add to 120 - the next possible lower value.
B1 + B3 = 112
B3 + B5 = 120
Substituting B3 = 58, we get B1 = 54 and B5 = 62
From 2 & 3 equations, we get B2 = 56 and B4 = 59
Hence, the weight of five bales are 54, 56, 58, 59 and 62 pounds.

Answered: You have 3 points labelled A, B and C. You then have another 3 points labelled

Thu, 29 Mar 2012 14:27:23 +0000

There is no solution to it, if you consider 2 dimensions. It is impossible to join
each of points A, B and C with points 1, 2 and 3 without lines crossing each
other.
There is solution, if you consider 3 dimensions. Consider a circular base and a line perpendicular to it passing from the center. Now take any 3 points along the perimeter of the circular base as points 1, 2 and 3. Similarly take any 3 points along the perpendicular line as points A, B and C. Now it is quite simple to join each of points A, B and C with points 1, 2 and 3 without any of the lines crossing each other.
The other possible 3D structure is Pyramid. Take points 1, 2 and 3 as a vertices of the triangular base and points A, B and C along the height of the Pyramid which is perpendicular to the triangular base and passing through the apex.

Answered: If a bear eats 65 pounds in fish every day EXCEPT every 6th day which it only eats 45 pounds of fish. If the bear continues this, how many pounds of fish will it eat in 200 days?

Thu, 29 Mar 2012 14:26:46 +0000

The bear will eat 12,340 pounds of fish in 200 days.

It is given that on every 6th day bear eats 45 pounds of fish i.e. on day number 6,
12, 18, 24, … .. .. . 192, 198 the bear eats 45 pounds of fish.
Total number of 6th days = 200/6 = 33 (the bear eats 45 pounds)
Hence, the normal days are = 200 - 33 = 167 (the bear eats 65 pounds)
Thus, in 200 days, the bear will eat

= (167) * (65) + (33) * (45)
= 10855 + 1485
= 12,340 pounds

Answered: A frog starts climbing 15 feet wall. Each hour he climbs 3 feet and rests for 30

Thu, 29 Mar 2012 14:25:53 +0000

19 hours
A frog climbs 1 foot per 1 1/2 hours as during 30 minutes rest he slips back 2 feet. This way he will climb 12 feet in 18 hours. In next hour he will climb 3 more feet i.e. he will complete 15 feet in 19 hours and will reach the top of the wall

Answered: A man is on a search for Atlantis and comes upon an island where all the

Thu, 29 Mar 2012 14:25:04 +0000

There are 2 answers to it:
Answer I"Is the statement that you are reliable equivalent to the statement that
Atlantis is still around?"
Answer II"Do you believe that the Statement that you are a Fairy is equivalent to
the statement that Atlantis is still around?"

Answered: Replace each letter by a digit. Each letter must be represented by the same digit

Thu, 29 Mar 2012 14:24:03 +0000

Use trial and error. 0 =1, N = 8 ,E = 2, T = 7

Answered: What is the smallest number which when divided by 10 leaves a remainder of 9,

Thu, 29 Mar 2012 14:23:15 +0000

The smallest such number is 2519.
The easiest way is to find the Least Common Multiple (LCM) of 2, 3, 4, 5, 6, 7, 8
and 9. And subtract 1 from it.
The LCM of 2, 3, 4, 5, 6, 7, 8 and 9 is given by 2520. Hence, the required
number is 2519
Brain Teaser No : 00114
Everyday in his business a merchant had to weigh amounts from 1 kg to 121
kgs, to the nearest kg. What are the minimum number of different weights
required and how heavy should they be?
The minimum number is 5 and they should weigh 1, 3, 9, 27 and 81 kgs

Answered: Mrs. F has invited several wives of delegates to the United Nations for an

Thu, 29 Mar 2012 14:22:17 +0000

126 distinct seating arrangements are possible.
Mrs. J and Mrs. H must be together and Mrs. J must be at the end as Mrs. J
speaks only Russian and Mrs. H is the only other Russian speaker.
Mrs. L speaks only French and there are two others - Mrs. G and Mrs. M - who
speak French. Here there are 2 cases.
• CASE A : Mrs. L is at the other end
If Mrs. L is at the other end, either Mrs. G or Mrs. M must seat next to her.
o CASE AA : Mrs. G seats next to Mrs. L
Then, Mrs. M must seat next to Mrs. G and Mrs. N must seat next to Mrs. M. This is because Mrs. M speaks French and German, and
Mrs. N is the only other German speaker. Thus, the possible seating arrangement is JHxxxNMGL, where x is the English
speakers. Mrs. F, Mrs. K and Mrs. O can be arranged in remaining 3 positions in 3! different ways i.e. 6 ways.
o CASE AB : Mrs. M seats next to Mrs. L
If so, then either Mrs. N or Mrs. G must seat next to Mrs. M

Answered: There are N secret agents each know a different piece of secret information.

Thu, 29 Mar 2012 14:20:42 +0000

(2N - 3) telephone calls, for N = 2,3
(2N - 4) telephone calls, for N > 3
Divide the N secret agents into two groups. If N is odd, one group will contain
one extra agent.
Consider first group: agent 1 will call up agent 2, agent 2 will call up agent 3 and so on. Similarly in second group, agent 1 will call up agent 2, agent 2 will call up agent 3 and so on. After (N - 2) calls, two agents in each the group will know anything that anyone knew in his group, say they are Y1 & Y2 from group 1 and Z1 & Z2 from group 2.
Now, Y1 will call up Z1 and Y2 will call up Z2. Hence, in next two calls total of 4 agents will know everything.
Now (N - 4) telephone calls are reqiured for remaining (N - 4) secret agents.
Total telephone calls require are
= (N - 2) + 2 + (N - 4)
= 2N - 4
Let's take an example. Say there are 4 secret agents W, X, Y & Z. Divide them
into two groups of 2 each i.e. (W, X) and (Y, Z). Here, 4 telephone calls are
required.
1. W will call up X.
2. Y will call up Z.
3. W, who knows WX will call up Y, who knows YZ.
4. X, who knows WX will call up Z, who knows YZ.

Take an another example. Say there are 5 secret agents J, K, L, M & N. Divide
them into two groups i.e. (J, K) and (L, M, N). Here, 6 telephone calls are
required.
1. J will call up K.
2. L will call up M.
3. M will call up N. Now M and N know LMN.
4. J, who knows JK will call up M, who knows LMN.
5. K, who knows JK will call up N, who knows LMN.
6. L will call up to anyone of four.

Answered: A person travels on a cycle from home to church on a straight road with wind

Thu, 29 Mar 2012 14:20:11 +0000

Let distance between home and church is D.
A person took 4 hours to reach church. So speed while travelling towards church
is D/4.
Similarly, he took 3 hours to reach home. So speed while coming back is D/3.
There is a speed difference of 7 * D/12, which is the wind helping person in 1
direction, & slowing him in the other direction. Average the 2 speeds, & you have
the speed that person can travel in no wind, which is 7 * D/24.
Hence, person will take D / (7 * D/24) hours to travel distance D which is 24/7
hours.
Answer is 3 hours 25 minutes 42 seconds

Answered: Sam and Mala have a conversation. • Sam says I am certainly not over 40

Thu, 29 Mar 2012 14:19:40 +0000

Sam is 41 and Mala is 37.
Let's invert the teaser and read it like this :
• Sam says I am certainly over 40
• Mala says I am not 38 and you are atmost 4 years older than me
• Now Sam says you are atmost 38
From first statement it is clear that Sam is over 40. Also, from next 2 statements
it is clear that Mala is less then 38. Hence the possibilities are :
Sam = 41, 42, 43, 44, 45, ......
Mala = 37, 36, 35, 34, 33, ......
It also says that the difference between their age is maximum 4 years. Hence,
there is only one possible pair i.e. 41 and 37, all other combination have
differences more then 4.
Hence the answer - Sam is 41 and Mala is 37.

Answered: Jack and Jill are playing cards for a stake of $1 a game. At the end of the

Thu, 29 Mar 2012 14:19:02 +0000

They played total of 9 games. Jack won 3 games and Jill won 6 games.
If Jack has won three games and Jill has won $3, she lost a dollar for each loss,
therefore she has won 6 and lost 3 to make $3 and he won the other 3 that she
lost!

Answered: bought a car with a peculiar 5 digit numbered licence plate which on reversing

Thu, 29 Mar 2012 14:18:28 +0000

Only 0 1 6 8 and 9 can be read upside down. So on rearranging these digits we
get the answer as 10968.

Answered: A farmer needs 8 gallons of water. He has only three unmared buckets, two 6 gallon and one 11 gallon bucket.

Thu, 29 Mar 2012 14:17:53 +0000

Here is the solution with 10 gallon water wastage.
OPERATIONS 6 6 11

Fill 6 gallon bucket with water 6 0 0
Empty 6 gallon bucket into 11 gallon bucket 0 0 6
Fill 6 gallon bucket with water 6 0 6
Fill 11 gallon bucket to full using filled 6 gallon bucket. This will leave 1
gallon water in 6 gallon bucket 1 0 11
Empty 11 gallon bucket into second 6 gallon bucket. 1 6 5
Empty 11 gallon bucket - wastage of 5 gallon water 1 6 0
Empty second 6 gallon bucket into 11 gallon bucket 1 0 6
Fill seccond 6 gallon bucket with water 1 6 6
Fill 11 gallon bucket to full using filled second 6 gallon bucket. This will
leave 1 gallon water in second 6 gallon bucket 1 1 11
Fill first 6 gallon bucket with 1 gallon water which is in second 6 gallon
bucket 2 0 11
Empty 11 gallon bucket into second 6 gallon bucket. 2 6 5
Empty 11 gallon bucket - wastage of 5 gallon water 2 6 0
Fill 11 gallon bucket with water in both the 6 gallon buckets 0 0 11
I

Answered: Consider a chessboard with a single Rook. A Rook can move any number of

Thu, 29 Mar 2012 14:17:08 +0000

16 moves
As a Rook can move any number of square sideways/forward, but not diagonally and there are 8 rows and 8 columns on the chessboard; the Rook needs minimum 16 moves to pass over all the squares and return to the original position.

Answered: 4 men can dig 4 holes in 4 days. How many hours does it take for 1 man to dig half a hole?

Thu, 29 Mar 2012 14:16:41 +0000

There is nothing like "HALF HOLE".

Answered: Jim lies a lot. He tells the truth on only one day in a week.

Thu, 29 Mar 2012 14:16:17 +0000

Jim tells the truth on Tuesday.
As Jim tells truth only on one day in a week, his statement on day 1 and day 3
both can not be false. Otherwise he tells truth on more than one days in a week.
Also, all three statements are mad on three consecutive days, statement made
on day 1 and day 3 both can not be true. Thus, either the statement made on day 1 or day 3 is true and other is false. Also, the statement made on day 2 must be false i.e. day 1 is not Saturday, Friday or Wednesday.
Let's assume that the statement 1 is true. Then from the statement 3, day 1 must be either Friday or Wednesday. But it is already deduced that day 1 is not Saturday, Friday or Wednesday.
Hence, the statement made on day 1 is false and the last statement is true. Then from
the statement 1, day 3 must be either Monday or Tuesday. But it is already deduced that day 1 can not be Saturday i.e. day 3 can't be Monday. Hence, Jim tells the truth on Tuesday.

Answered: Last Saturday Milan went for the late night show and came late. In the morning

Thu, 29 Mar 2012 14:15:44 +0000

Milan saw BOBBY.
The six movie names are - MONEY, JOHNY, BABLU, BHABI, ROBOT and
BUNNY.
Compare MONEY and JOHNY. They have O common at the second place and Y
common at the fifth place. Also, they can't have two different letters each,
common with the required movie as the letters in remaining three places are all different. Thus, the required movie must have either O at the second place or Y
at the fifth place or both.
Similarly, comparing JOHNY and BUNNY - the required movie must have either
N at the fourth place or Y at the fifth place or both. Also, comparing MONEY and
BUNNY - the required movie must have either N at the third place or Y at the fifth
place or both.
From the above 3 deduction, either Y is at fifth place or O is at the second place
and N is at the third & fourth place. The later combination is not possible as BABLU, BHABI & ROBOT will need at least 3 other letters which makes the required movie 6 letter long. Hence, the required movie must have Y at the fifth place.
Now Y is not there in BABLU and BHABI at the fifth place and they have only B common at the first place. Hence, B must be the first letter.
As B is at the first place and Y is at the fifth place and every movie has exactly 2
letters common with the required movie. From BUNNY, the required movie do not have U at the second place and N at the third and fourth place. Now looking at JOHNY and MONEY, they must have O common at the second place.
Using the same kind of arguments for BABLU, BHABI and ROBOT, we can conclude that Milan saw BOBBY.

Answered: Who is the Youngest?

Thu, 29 Mar 2012 14:14:52 +0000

Discard whoever are older than someone.
From (1) Gurmit is younger than Dinesh and Farukh.
From (5) Jatin is younger than Irfan and Gurmit.
From (2) Eshrat is younger than Jatin and Chandu.
From above 3 deductions, Eshrat is younger than Dinesh, Farukh, Irfan, Gurmit,
Jatin and Chandu.
Also,
From (3) Chandu is younger than Amit and Irfan.
From (4) Hemant is younger than Farukh and Bhavin.
From (6) Gurmit is younger than Hemant.
From above 3 deductions, Gurmit is younger than Farukh, Bhavin and Hemant.
Also, Chandu is younger than Amit and Irfan. But as seen earlier, Eshrat is
younger than Gurmit and Chandu.
Hence, Eshrat is the youngest.

Answered: A man was looking at a portrait. Someone asked him, "Whose picture are you

Thu, 29 Mar 2012 14:14:29 +0000

The man is looking at his FATHER's portrait.
"my father's son" is the man himself as he do not have any brothers and sisters.
So the statement reduces to "this man's son is myself." Now it is clear that the portrait is of his father.
Given the following facts:

Answered: In the village called TALAJA, only three TV channels are available - Moon

Thu, 29 Mar 2012 14:13:28 +0000

300 viewers watch all three channels.
Let's assume that total X viewers watch all three channels.
total viewers who watch only Moon Plus and Mony = 500-X
total viewers who watch only Moon Plus and Mee TV = 800-X
total viewers who watch only Mony and Mee TV = 1000-X
total viewers who watch only Moon Plus
= 1500 - (500-X) - (800-X) - X
= 200 + X
total viewers who watch only Mony
= 2000 - (500-X) - (1000-X) - X
= 500 + X
total viewers who watch only Mee TV
= 2500 - (1000-X) - (800-X) - X
= 700 + X
We know that total viewers are 4000. Summing up all 7 values,
X + (500 - X) + (800 - X) + (1000 - X) + (200 + X) + (500 + X) + (700 + X) = 4000
X + 3700 = 4000
X = 300
Hence, total 300 viewers watch all three channels.

Answered: The secret agent X emailed some code to his head office. They are "RADAR,

Thu, 29 Mar 2012 14:12:56 +0000

The fake code-word is MOTOR.
All the code-words except MOTOR are Palindromes.