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<title>Prepjunk - Recent questions and answers</title>
<link>http://www.prepjunk.com/qa</link>
<description>Powered by Question2Answer</description>
<item>
<title>What are the other options for gonorrhea treatment?</title>
<link>http://www.prepjunk.com/4097/what-are-the-other-options-for-gonorrhea-treatment</link>
<description>&lt;p&gt;I would like to know, what the other options for gonorrhea treatment are. because one of my family member is suffering from this disease. Please help me finding a proper treatment about this disease. Thank you.&lt;/p&gt;
</description>
<category>IITJEE</category>
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<pubDate>Sat, 18 May 2013 22:07:42 +0000</pubDate>
</item>
<item>
<title>Which is the best engagement ring website?</title>
<link>http://www.prepjunk.com/4096/which-is-the-best-engagement-ring-website</link>
<description>&lt;p&gt;I would like to know, which is the best engagement ring website? Since, I am looking to purchase engagement ring for my son. Please suggest me a website thank you.&lt;/p&gt;
</description>
<category>IITJEE</category>
<guid isPermaLink="true">http://www.prepjunk.com/4096/which-is-the-best-engagement-ring-website</guid>
<pubDate>Wed, 15 May 2013 06:20:55 +0000</pubDate>
</item>
<item>
<title>Control Valve</title>
<link>http://www.prepjunk.com/4095/control-valve</link>
<description>&lt;ol&gt;
&lt;li&gt;How do ou reverse the action of a valve without using the positioner?&lt;/li&gt;
&lt;li&gt;Why do we usse a positioner? Give one reason.&lt;/li&gt;
&lt;li&gt;Give two methods to reverse the action of a valve.&lt;/li&gt;
&lt;li&gt;Why is there air to close and air to open valves?&lt;/li&gt;
&lt;/ol&gt;
</description>
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<pubDate>Sat, 13 Apr 2013 06:24:24 +0000</pubDate>
</item>
<item>
<title>13a d/p cell</title>
<link>http://www.prepjunk.com/4094/13a-d-p-cell</link>
<description>&lt;ol&gt;
&lt;li&gt;When the static alignment is complete,what is the maximum amount the zero may shift yhe diaphragm is pressurized? &lt;/li&gt;
&lt;li&gt;How do you determine that the setting of the relay is correct?&lt;/li&gt;
&lt;li&gt;What is meant by elevating and suppressing the transmitter?&lt;/li&gt;
&lt;/ol&gt;
</description>
<guid isPermaLink="true">http://www.prepjunk.com/4094/13a-d-p-cell</guid>
<pubDate>Sat, 13 Apr 2013 06:18:06 +0000</pubDate>
</item>
<item>
<title>13a d/p cell</title>
<link>http://www.prepjunk.com/4093/13a-d-p-cell</link>
<description>&lt;p&gt;when adjusting the static alignment, what is the maximum amout the zero may shift when locking the C-flexture?&lt;/p&gt;
</description>
<guid isPermaLink="true">http://www.prepjunk.com/4093/13a-d-p-cell</guid>
<pubDate>Sat, 13 Apr 2013 06:12:38 +0000</pubDate>
</item>
<item>
<title>Answered: Can anyone share facts about Intelligence quotient?</title>
<link>http://www.prepjunk.com/4091/can-anyone-share-facts-about-intelligence-quotient?show=4092#a4092</link>
<description>&lt;p&gt;There are many famous personalities have taken this test but first ever IQ test was taken by Alfred Binet in 1894 and later Alfred-Simon made a scale on IQ test. Name of the test which is &lt;a rel=&quot;nofollow&quot; href=&quot;http://iknow.fm/blog/iq-testing-how-did-it-begin/&quot;&gt;intelligence quotient&lt;/a&gt; (IQ) was given by Lewis Terman in 1915. For more facts about Intelligence quotient please visit this source: &lt;a rel=&quot;nofollow&quot; href=&quot;http://iknow.fm/blog/iq-testing-how-did-it-begin/&quot;&gt;http://iknow.fm/blog/iq-testing-how-did-it-begin/&lt;/a&gt;&lt;/p&gt;
</description>
<category>IITJEE</category>
<guid isPermaLink="true">http://www.prepjunk.com/4091/can-anyone-share-facts-about-intelligence-quotient?show=4092#a4092</guid>
<pubDate>Sun, 24 Mar 2013 20:56:09 +0000</pubDate>
</item>
<item>
<title>Answered: Is there will be time limit for PALS examination?</title>
<link>http://www.prepjunk.com/4089/is-there-will-be-time-limit-for-pals-examination?show=4090#a4090</link>
<description>&lt;p&gt;PALS examination is not a time limit examination. You can take your time to complete your examination. It is really important course. Since, it deals with emergency situation for ill infants and children. You can get bulk &lt;a rel=&quot;nofollow&quot; href=&quot;https://advancedmedicalcertification.com/pals-certification&quot;&gt;PALS certification discount&lt;/a&gt; easily you need to contact vendor. Some websites are offering like 15% discount. Try to visit them as soon as possible. &lt;/p&gt;
</description>
<category>IITJEE</category>
<guid isPermaLink="true">http://www.prepjunk.com/4089/is-there-will-be-time-limit-for-pals-examination?show=4090#a4090</guid>
<pubDate>Sat, 23 Feb 2013 00:34:11 +0000</pubDate>
</item>
<item>
<title>Answered: Can we purchase more than 1 course of ACLS certification?</title>
<link>http://www.prepjunk.com/4086/can-we-purchase-more-than-1-course-of-acls-certification?show=4087#a4087</link>
<description>&lt;p&gt;Yes, you can take up more than 1 course of ACLS certification. You can get a 15% discount if you take up the course. ACLS certification discount is been offered by different websites at different discount rates. For more information on &lt;a rel=&quot;nofollow&quot; href=&quot;https://advancedmedicalcertification.com/acls-certification&quot;&gt;ACLS certification discount&lt;/a&gt; please visit this website: &lt;a rel=&quot;nofollow&quot; href=&quot;https://advancedmedicalcertification.com/acls-certification&quot;&gt;&lt;/a&gt;&lt;a rel=&quot;nofollow&quot; href=&quot;https://advancedmedicalcertification.com/acls-certification&quot;&gt;https://advancedmedicalcertification.com/acls-certification&lt;/a&gt;  &lt;/p&gt;
</description>
<category>IITJEE</category>
<guid isPermaLink="true">http://www.prepjunk.com/4086/can-we-purchase-more-than-1-course-of-acls-certification?show=4087#a4087</guid>
<pubDate>Tue, 12 Feb 2013 20:25:50 +0000</pubDate>
</item>
<item>
<title>Answered: Do java blogs chargers users who visit their blogs?</title>
<link>http://www.prepjunk.com/4084/do-java-blogs-chargers-users-who-visit-their-blogs?show=4085#a4085</link>
<description>&lt;p&gt;Hello, I am looking to learn java from java blogs do they charge us for coding and some sort of study materials if we visit and start learning java from them? Please share with me.&lt;/p&gt;

&lt;p&gt;Answer: Some of the java blogs do charge you and some of the java blogs doesn’t charge you.  But, they are free blogs who are offering excellent study material for students who are looking to study java. &lt;/p&gt;

&lt;p&gt;For more information please visit this website: &lt;a rel=&quot;nofollow&quot; href=&quot;http://www.java-forums.org/blogs/&quot;&gt;http://www.java-forums.org/blogs/&lt;/a&gt;&lt;/p&gt;
</description>
<category>IITJEE</category>
<guid isPermaLink="true">http://www.prepjunk.com/4084/do-java-blogs-chargers-users-who-visit-their-blogs?show=4085#a4085</guid>
<pubDate>Sat, 26 Jan 2013 05:48:26 +0000</pubDate>
</item>
<item>
<title>Which is the best SEO company on internet ?</title>
<link>http://www.prepjunk.com/4081/which-is-the-best-seo-company-on-internet</link>
<description>&lt;p&gt;I am searching for a SEO company which is providing an excellent SEO SERVICES. So, i can look to promote my website thanks in advance.&lt;/p&gt;
</description>
<guid isPermaLink="true">http://www.prepjunk.com/4081/which-is-the-best-seo-company-on-internet</guid>
<pubDate>Sat, 27 Oct 2012 19:38:26 +0000</pubDate>
</item>
<item>
<title>Is it  true that deer antler velvet even famous for anti-aging properties?</title>
<link>http://www.prepjunk.com/4080/true-that-deer-antler-velvet-even-famous-anti-aging-properties</link>
<description>&lt;p&gt;I am just performing a analysis on &lt;a rel=&quot;nofollow&quot; href=&quot;http://deerantlervelvetbenefits.com&quot;&gt;deer antler spray side effects&lt;/a&gt;  for the humans. I want to know whether it also has anti-aging characteristics also. I am a little confused because I haven’t see that clearly just about anywhere with the exception of a few of the places&lt;/p&gt;
</description>
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<pubDate>Wed, 19 Sep 2012 20:10:23 +0000</pubDate>
</item>
<item>
<title>Given a char array find possible soln like</title>
<link>http://www.prepjunk.com/4079/given-a-char-array-find-possible-soln-like</link>
<description>&lt;p&gt;Given a char array find possible soln like :&lt;br&gt;
eg for &quot;abc&quot;&lt;br&gt;
ans: {a,ab,abc.b,bc,c}&lt;/p&gt;

&lt;p&gt;char[] function(char[])&lt;/p&gt;
</description>
<category>C++</category>
<guid isPermaLink="true">http://www.prepjunk.com/4079/given-a-char-array-find-possible-soln-like</guid>
<pubDate>Fri, 31 Aug 2012 05:45:18 +0000</pubDate>
</item>
<item>
<title>Answered: wireless firmware missing error in fedora 17</title>
<link>http://www.prepjunk.com/4077/wireless-firmware-missing-error-in-fedora-17?show=4078#a4078</link>
<description>&lt;p&gt;Just try this command :&lt;/p&gt;

&lt;pre&gt;&lt;code&gt;wget http://downloads.openwrt.org/sources/broadcom-wl-4.150.10.5.tar.bz2
tar xjf broadcom-wl-4.150.10.5.tar.bz2
cd broadcom-wl-4.150.10.5/driver    
su
b43-fwcutter -w /lib/firmware wl_apsta_mimo.o
&lt;/code&gt;&lt;/pre&gt;
</description>
<category>Computer  Technology</category>
<guid isPermaLink="true">http://www.prepjunk.com/4077/wireless-firmware-missing-error-in-fedora-17?show=4078#a4078</guid>
<pubDate>Fri, 17 Aug 2012 19:50:28 +0000</pubDate>
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<item>
<title>Answered: What is Difference between ref and inout signal ?</title>
<link>http://www.prepjunk.com/4075/what-is-difference-between-ref-and-inout-signal?show=4076#a4076</link>
<description>&lt;p&gt;ref and inout mean different things depending on whether you are talking about structural ports of a module/program/interface or procedural arguments to a task/function. &lt;/p&gt;

&lt;p&gt;For port directions, there is very little difference in functionality between ref and inout; they essentially mean that the two signals that are getting connected are collapsed into a single signal. There are a few differences in restrictions including that the signals connecting to a ref port must be both variables and the signals connecting to an inout port must both be wires. &lt;/p&gt;

&lt;p&gt;For argument directions, all signals are variables. An inout argument means that signals are copied into a set of local variables upon entry to a task/function, and copied out upon exiting. A ref argument means the local variables are not separate variables, they are symbolic references to the variables used by the caller. &lt;/p&gt;

&lt;p&gt;The only situation where there is a visible difference in the functionality between ref and inout arguments is when the arguments are part of a blocking task. With an inout, if the calling signal changes while the task is blocked, the local signal does not change. And if the blocking task changes the local signal, the calling signal does not get changed until the task exits. With ref argument, the calling signal and the local signal are always in sync.&lt;/p&gt;
</description>
<category>Electronics engineering</category>
<guid isPermaLink="true">http://www.prepjunk.com/4075/what-is-difference-between-ref-and-inout-signal?show=4076#a4076</guid>
<pubDate>Mon, 06 Aug 2012 10:47:16 +0000</pubDate>
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<item>
<title>Answered: calculate th equilibrium concentrations of H+, benzote anion and benzoic acid. The initial concentration of benzoic acid is 0.10 M</title>
<link>http://www.prepjunk.com/4040/calculate-equilibrium-concentrations-benzoic-concentration?show=4041#a4041</link>
<description>&lt;p&gt;Ka of benzoic acid is 6.3x10^-5&lt;/p&gt;

&lt;p&gt;C6H5COOH &amp;lt;===&amp;gt;C6H5COO- + H+&lt;br&gt;
Ka= [C6H5COO-][H+]/[C6H5COOH]&lt;br&gt;
[C6H5COOH] = 0.1&lt;br&gt;
[C6H5COO-]=[H+]= x&lt;br&gt;
=&amp;gt;Ka= x2/[C6H5COOH] =&amp;gt; x = √(Ka * [C6H5COOH]) = √ 6.3x10^-5 * 0.1) = 2.509 *10^-3&lt;/p&gt;
</description>
<category>Chemistry</category>
<guid isPermaLink="true">http://www.prepjunk.com/4040/calculate-equilibrium-concentrations-benzoic-concentration?show=4041#a4041</guid>
<pubDate>Mon, 30 Apr 2012 13:13:39 +0000</pubDate>
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<title>Answered: compare properties of molecule formed from atoms in similar families: for example, H2S VERSUS H2O.</title>
<link>http://www.prepjunk.com/4038/compare-properties-molecule-formed-similar-families-example?show=4039#a4039</link>
<description>&lt;p&gt;H2S and H2O have similar molecular structures.&lt;br&gt;
Angle of molecule&lt;br&gt;
Both are BENT shaped molecules&lt;br&gt;
H2O has the Hydrogen molecules about 104 degrees apart&lt;br&gt;
H2S has the Hydrogen molecules spaced at about 92 degrees&lt;/p&gt;

&lt;p&gt;Forces&lt;br&gt;
H2O exhibits London Dispersion ForcesH2O is the only one of the two that is influenced by Hydrogen Bonds. Oxygen is electronegative enough to make the molecule extremely polar&lt;br&gt;
H2S = has london dispersion forces but not strong Hydrogen bonding as Sulphur is not so influencing enough&lt;/p&gt;

&lt;p&gt;so H2O is liquid and H2S is a gas&lt;br&gt;
due to hydrogen bonding H2O has higher boiling point than H2S&lt;/p&gt;
</description>
<category>Chemistry</category>
<guid isPermaLink="true">http://www.prepjunk.com/4038/compare-properties-molecule-formed-similar-families-example?show=4039#a4039</guid>
<pubDate>Mon, 30 Apr 2012 13:10:46 +0000</pubDate>
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<item>
<title>Answered: Explain in your own words how an Arago's Disk works.</title>
<link>http://www.prepjunk.com/3981/explain-in-your-own-words-how-an-aragos-disk-works?show=4037#a4037</link>
<description>&lt;p&gt;Whenever an enclosed copper disk was rotated by the diving pulley inside an enclosure, the compass needle outside the enclosure would spin around. Many scientists had labored at various explanations for this strange action, but it was Faraday who finally resolved the mystery. Faraday's discovery of electromagnetic induction revealed that rotation of the compass needle was the result of interaction between the magnetic needle and the disk.&lt;/p&gt;

&lt;p&gt;The magnetic needle induced a current in the moving disk, which in turn set up a magnetic field. This induced magnetic field (caused by the induced current in the disk) would now interact with the magnetic needle and thus causing it to spin.&lt;/p&gt;

&lt;p&gt;In 1824, Arago designed an experiment known as Arago's disk , which showed that a needle suspended on a pivot held above a spinning copper disk will follow the rotation of the copper disk. What was impressive about Arago's apparatus was its utilization of copper, a nonmagnetic substance; that is, the experiment seemed to show that mere motion could induce magnetism in&lt;br&gt;
a metal object. Arago's copper disk caused a commotion. Arago found that the other metals exhibited similar effects. Silver showed a greater effect than copper, whereas lead, mercury, and bismuth were less effective. Ampere also worked on this problem during the summer of 1826 and finally replicated Arago s experiment after substituting a solenoid (a coil of wire around a metallic core) for the magnet of Arago's original experiment. Poisson published a theoretic memoir on&lt;br&gt;
the subject, but no cause could be assigned for so extraordinary an action.&lt;/p&gt;
</description>
<category>Physics</category>
<guid isPermaLink="true">http://www.prepjunk.com/3981/explain-in-your-own-words-how-an-aragos-disk-works?show=4037#a4037</guid>
<pubDate>Sun, 29 Apr 2012 05:43:36 +0000</pubDate>
</item>
<item>
<title>Answered: How do you convert inches to pixels?</title>
<link>http://www.prepjunk.com/4033/how-do-you-convert-inches-to-pixels?show=4034#a4034</link>
<description>&lt;p&gt;Multiply the number of inches by the number of pixels per inch.&lt;br&gt;
But this number is dynamic and depends on the monitor.&lt;/p&gt;
</description>
<category>Software</category>
<guid isPermaLink="true">http://www.prepjunk.com/4033/how-do-you-convert-inches-to-pixels?show=4034#a4034</guid>
<pubDate>Fri, 27 Apr 2012 11:42:56 +0000</pubDate>
</item>
<item>
<title>Answered: balancing redox reaction</title>
<link>http://www.prepjunk.com/4031/balancing-redox-reaction?show=4032#a4032</link>
<description>&lt;p&gt;Zn(0H)2(s) + 2 H&lt;a rel=&quot;nofollow&quot; href=&quot;aq&quot;&gt;+&lt;/a&gt; =&amp;gt; Zn&lt;a rel=&quot;nofollow&quot; href=&quot;aq&quot;&gt;2+&lt;/a&gt; + 2 H20(l)&lt;br&gt;
Zn(0H)2(s) + 2 OH&lt;a rel=&quot;nofollow&quot; href=&quot;aq&quot;&gt;-&lt;/a&gt; =&amp;gt; Zn(OH4)&lt;a rel=&quot;nofollow&quot; href=&quot;aq&quot;&gt;2-&lt;/a&gt;&lt;/p&gt;
</description>
<category>Chemistry</category>
<guid isPermaLink="true">http://www.prepjunk.com/4031/balancing-redox-reaction?show=4032#a4032</guid>
<pubDate>Tue, 24 Apr 2012 04:37:32 +0000</pubDate>
</item>
<item>
<title>Answered: What is being calculated when the molarity of a solute in a solution is multiplied by the volume of the solution in liters</title>
<link>http://www.prepjunk.com/4029/calculated-molarity-solute-solution-multiplied-solution?show=4030#a4030</link>
<description>&lt;p&gt;Molarity = moles/volume(liter) &lt;br&gt;
Moles = molarity * volume(liter) &lt;br&gt;
So the number of moles of solute is being calculated&lt;/p&gt;
</description>
<category>Chemistry</category>
<guid isPermaLink="true">http://www.prepjunk.com/4029/calculated-molarity-solute-solution-multiplied-solution?show=4030#a4030</guid>
<pubDate>Tue, 24 Apr 2012 04:34:58 +0000</pubDate>
</item>
<item>
<title>Answered: Which of the following isotopes is most effective in imaging of the heart?</title>
<link>http://www.prepjunk.com/4027/which-following-isotopes-most-effective-imaging-the-heart?show=4028#a4028</link>
<description>&lt;p&gt;Answer: 5) 99Tc&lt;/p&gt;
</description>
<category>Chemistry</category>
<guid isPermaLink="true">http://www.prepjunk.com/4027/which-following-isotopes-most-effective-imaging-the-heart?show=4028#a4028</guid>
<pubDate>Tue, 24 Apr 2012 04:33:46 +0000</pubDate>
</item>
<item>
<title>Answered: In converting Br2 from a liquid to a gas, which intermolecular forces must be overcome?</title>
<link>http://www.prepjunk.com/4025/converting-liquid-which-intermolecular-forces-must-overcome?show=4026#a4026</link>
<description>&lt;p&gt;The answer is: London dispersion forces&lt;br&gt;
Br2 is a non-polar diatomic molecule, and the only inter-molecular forces present are London dispersion forces&lt;/p&gt;
</description>
<category>Chemistry</category>
<guid isPermaLink="true">http://www.prepjunk.com/4025/converting-liquid-which-intermolecular-forces-must-overcome?show=4026#a4026</guid>
<pubDate>Tue, 24 Apr 2012 04:32:35 +0000</pubDate>
</item>
<item>
<title>Answered: What is sin^2 θ = 4 sin θ + 5?</title>
<link>http://www.prepjunk.com/4023/what-is-sin-2-%CE%B8-4-sin-%CE%B8-5?show=4024#a4024</link>
<description>&lt;p&gt;sin^2 θ = 4 sin θ + 5&lt;br&gt;
Write sin θ = z &lt;br&gt;
z^2 - 4 * z - 5 = 0 &lt;br&gt;
(z + 1) * (z - 5) = 0 &lt;br&gt;
z = -1 or z = 5 &lt;br&gt;
As z = sin θ, and sin θ cannot be outside the range +1 to -1, only z = -1 is valid &lt;br&gt;
θ =  3 * pi/2 = 4.712 radians&lt;/p&gt;
</description>
<category>Trigonometry</category>
<guid isPermaLink="true">http://www.prepjunk.com/4023/what-is-sin-2-%CE%B8-4-sin-%CE%B8-5?show=4024#a4024</guid>
<pubDate>Sat, 21 Apr 2012 11:11:26 +0000</pubDate>
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<item>
<title>Answered: A mixture consisting of .150 mol H2 and .150 mol I2 is brought to equilibrium at 445 degrees celcius in a 3.25 L flask. What are the equilibrium amounts of H2, I2, and HI</title>
<link>http://www.prepjunk.com/4021/consisting-brought-equilibrium-celcius-equilibrium-amounts?show=4022#a4022</link>
<description>&lt;p&gt;H2(g) + I2 (g) --&amp;gt; 2HI(g) Kc=50.2 at 445 degrees celcius&lt;/p&gt;

&lt;p&gt;Let x be the change in moles&lt;/p&gt;

&lt;pre&gt;&lt;code&gt;          H2(g)          +        I2 (g) =======&amp;gt; 2HI(g)

I       0.150                      0.150                      0
C         -x                         -x                      +2x
E     0.150-x                     0.150-x                     2x
&lt;/code&gt;&lt;/pre&gt;

&lt;p&gt;equilibrium constant = [product]/reactant]&lt;br&gt;
50.42 = [HI]^2/[H2][I2]&lt;br&gt;
50.42 = (2x)^2/(0.150-x)^2&lt;br&gt;
50.42 = (2x/0.150-x)^2&lt;br&gt;
sqr(50.42)=2x/0.150&lt;br&gt;
7.1 = 2x/0.150&lt;br&gt;
x =(7.1 * 0.150)/2=0.5325&lt;/p&gt;

&lt;p&gt;[H2]= 0.5325 mol : [I2]=0.5325 mol : [HI] =2 * 0.5325=1.06 mol&lt;/p&gt;
</description>
<category>Chemistry</category>
<guid isPermaLink="true">http://www.prepjunk.com/4021/consisting-brought-equilibrium-celcius-equilibrium-amounts?show=4022#a4022</guid>
<pubDate>Sat, 21 Apr 2012 05:34:26 +0000</pubDate>
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<item>
<title>Answered: Why, in a primitive cubic cell, do anions sit on the lattice points while the cation fills the lattice hole in the center?</title>
<link>http://www.prepjunk.com/4019/primitive-anions-lattice-points-while-cation-lattice-center?show=4020#a4020</link>
<description>&lt;p&gt;d. Because cations are smaller than anions and fit better inside lattice holes.&lt;/p&gt;
</description>
<category>Chemistry</category>
<guid isPermaLink="true">http://www.prepjunk.com/4019/primitive-anions-lattice-points-while-cation-lattice-center?show=4020#a4020</guid>
<pubDate>Sat, 21 Apr 2012 05:32:12 +0000</pubDate>
</item>
<item>
<title>Answered: CsCl crystallizes in a unit cell that contains the Cs+ ion at the center of a cube that has a Cl- at each corner.</title>
<link>http://www.prepjunk.com/4017/cscl-crystallizes-cell-contains-center-cube-that-each-corner?show=4018#a4018</link>
<description>&lt;p&gt;Answer: e. 1 and 1&lt;/p&gt;
</description>
<category>Chemistry</category>
<guid isPermaLink="true">http://www.prepjunk.com/4017/cscl-crystallizes-cell-contains-center-cube-that-each-corner?show=4018#a4018</guid>
<pubDate>Sat, 21 Apr 2012 05:31:10 +0000</pubDate>
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<item>
<title>Answered: What is the net redox reaction that occurs when Cu comes into contact with acidic K2Cr2O7?</title>
<link>http://www.prepjunk.com/4015/what-redox-reaction-occurs-comes-contact-with-acidic-k2cr2o7?show=4016#a4016</link>
<description>&lt;p&gt;Oxidation: Cu =&amp;gt; Cu(2+) + 2 e-&lt;br&gt;
Reduction: Cr207(2-) + 14 H+ + 6e- =&amp;gt; 2 Cr(3+) + 7 H20&lt;br&gt;
Add 3 x Oxidation + Reduction and cancel electrons to get&lt;br&gt;
net redox reaction:&lt;br&gt;
3 Cu + Cr207(2-) + 14 H+ =&amp;gt; 3 Cu2+ + 2 Cr(3+) + 7 H20&lt;br&gt;
Eo(cell) = Eo(Cr207 [2-] /Cr3+) - Eo(Cu2+/Cu)&lt;br&gt;
= 1.33-0.34&lt;br&gt;
= +0.99 V&lt;/p&gt;
</description>
<category>Chemistry</category>
<guid isPermaLink="true">http://www.prepjunk.com/4015/what-redox-reaction-occurs-comes-contact-with-acidic-k2cr2o7?show=4016#a4016</guid>
<pubDate>Sat, 21 Apr 2012 05:29:29 +0000</pubDate>
</item>
<item>
<title>Answered: Equal volumes of the following pairs of solutions are mixed. Which pair will produce a buffer solution?</title>
<link>http://www.prepjunk.com/4013/volumes-following-solutions-mixed-produce-buffer-solution?show=4014#a4014</link>
<description>&lt;p&gt;in buffer we should have weak acid/weak base and salt or  weak base and strong acid or weak acid and strong base&lt;br&gt;
so&lt;br&gt;
here as the acid is strong , base molarity &amp;gt; acid molaryty&lt;br&gt;
hence&lt;br&gt;
C. 0.10 M HCl and 0.15 M NH3&lt;/p&gt;
</description>
<guid isPermaLink="true">http://www.prepjunk.com/4013/volumes-following-solutions-mixed-produce-buffer-solution?show=4014#a4014</guid>
<pubDate>Sat, 21 Apr 2012 05:23:54 +0000</pubDate>
</item>
<item>
<title>Answered: An ant starts at the point (1,0) on the unit circle and walks counterclockwise at a distance of 3 units around the circle. Find x and y coordinates (attdp) of the final location of the ant.</title>
<link>http://www.prepjunk.com/4010/circle-counterclockwise-distance-around-coordinates-location?show=4011#a4011</link>
<description>&lt;p&gt;Since there are 2π radians in a circle (which corresponds to the circumference), traveling 3 units around the circle is the same as moving through an angle of 3 radians.  Therefore, the x and y coordinates of the ant are:&lt;br&gt;
(x,y) = (cos(3), sin(3)) = (-0.9900, 0.1411)&lt;/p&gt;
</description>
<category>Calculus</category>
<guid isPermaLink="true">http://www.prepjunk.com/4010/circle-counterclockwise-distance-around-coordinates-location?show=4011#a4011</guid>
<pubDate>Tue, 17 Apr 2012 14:36:02 +0000</pubDate>
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<item>
<title>Answered: The top of a 200 ft vertical tower is to be anchored by cables that make an angle of 30 degrees with the ground. How long must the cables be?</title>
<link>http://www.prepjunk.com/4008/vertical-tower-anchored-cables-angle-degrees-ground-cables?show=4009#a4009</link>
<description>&lt;p&gt;SIN 30= 200/X&lt;br&gt;
X=200/SIN 30= 400METERS long must the cables be&lt;br&gt;
TAN 30=200/Y&lt;br&gt;
Y=200√3=346.41 METERS from the base of the tower should anchors be placed&lt;/p&gt;
</description>
<category>Calculus</category>
<guid isPermaLink="true">http://www.prepjunk.com/4008/vertical-tower-anchored-cables-angle-degrees-ground-cables?show=4009#a4009</guid>
<pubDate>Tue, 17 Apr 2012 14:35:23 +0000</pubDate>
</item>
<item>
<title>Answered: Matias has a bag of 25 marbles, 13 white, and 12 black. What is the probability of Matias picking a white marble and without putting it back, then picks a black marble?</title>
<link>http://www.prepjunk.com/4006/matias-marbles-probability-matias-picking-without-putting?show=4007#a4007</link>
<description>&lt;p&gt;Matias has a bag of 25 marbles, 13 white, and 12 black. What is the probability of Matias picking a white marble and without putting it back, then picks a black marble?&lt;br&gt;
getting white marble: 13/25&lt;br&gt;
now getting black marble = 12/24 = 1/2&lt;br&gt;
now&lt;br&gt;
required probabiltiy = 13/25 * 1/2 = 13/50&lt;br&gt;
option A. 13/50  is answer&lt;/p&gt;
</description>
<category>Probability</category>
<guid isPermaLink="true">http://www.prepjunk.com/4006/matias-marbles-probability-matias-picking-without-putting?show=4007#a4007</guid>
<pubDate>Tue, 17 Apr 2012 14:33:52 +0000</pubDate>
</item>
<item>
<title>Answered: Mary has a bag of jelly beans: 6 green, 4 pink, 2 white, 5 yellow, 3 orange, and 1 purple. What are the chances of Mary blindly picking out 1 yellow jelly bean to eat?</title>
<link>http://www.prepjunk.com/4004/white-yellow-orange-purple-chances-blindly-picking-yellow?show=4005#a4005</link>
<description>&lt;p&gt;Mary has a bag of jelly beans: 6 green, 4 pink, 2 white, 5 yellow, 3 orange, and 1 purple. What are the chances of Mary blindly picking out 1 yellow jelly bean to eat?&lt;br&gt;
total = 6+4+2+5+3+1 = 21&lt;br&gt;
5 C 1 / ( 21 C 1 )&lt;br&gt;
= 5 / 21&lt;br&gt;
c. 5/21 is answer&lt;/p&gt;
</description>
<category>Probability</category>
<guid isPermaLink="true">http://www.prepjunk.com/4004/white-yellow-orange-purple-chances-blindly-picking-yellow?show=4005#a4005</guid>
<pubDate>Tue, 17 Apr 2012 14:32:45 +0000</pubDate>
</item>
<item>
<title>Answered: Will and Matt went bowling and played 5 games together. Their scores are listed here.</title>
<link>http://www.prepjunk.com/4002/matt-went-bowling-played-games-together-their-scores-listed?show=4003#a4003</link>
<description>&lt;p&gt;Will 125 67 150 111 77&lt;br&gt;
S.D = 34.21988&lt;br&gt;
Matt 121 135 91 109 59&lt;br&gt;
S.D = 29.42788&lt;br&gt;
a. will&lt;/p&gt;
</description>
<category>Probability</category>
<guid isPermaLink="true">http://www.prepjunk.com/4002/matt-went-bowling-played-games-together-their-scores-listed?show=4003#a4003</guid>
<pubDate>Tue, 17 Apr 2012 14:31:34 +0000</pubDate>
</item>
<item>
<title>Answered: X is normally distributed with mean 12 and standard deviation 4.  (a) Find the probability that X will be more than 10.</title>
<link>http://www.prepjunk.com/4000/normally-distributed-with-standard-deviation-probability?show=4001#a4001</link>
<description>&lt;p&gt;A) p(X &amp;gt; 10) = 1 - p(X &amp;lt;= 10) = 0.69&lt;br&gt;
B) P(X &amp;lt; 13.5) = P(X &amp;lt;= 13.5) = 0.646&lt;br&gt;
C) P(10 &amp;lt; X &amp;lt; 14.5) = P(X &amp;lt; 14.5) - P(X &amp;lt; 10) = P(X &amp;lt;= 14.5) - P(X &amp;lt;= 10) - 0.7340145 - 0.3085375&lt;br&gt;
D) 0.85 = 85% is the quantile.&lt;br&gt;
85% of this normal distribution lies below the value 'a'. P(X &amp;lt; 16.14573) =&lt;br&gt;
P(X &amp;lt;= 16.14573) = 0.85&lt;br&gt;
E) P(X &amp;gt; b) = 1 - P(X &amp;lt;= b) = 0.25;&lt;br&gt;
=&amp;gt; 1 - 0.25 - P(X &amp;lt;= b) = 0; 0.75 - P(X &amp;lt;= b) = 0; 0.75 = P(X &amp;lt;= b); P(X &amp;lt;= b) = 0.75.&lt;br&gt;
=&amp;gt; P(X &amp;lt;= 14.69796) = 0.75.&lt;/p&gt;
</description>
<category>Probability</category>
<guid isPermaLink="true">http://www.prepjunk.com/4000/normally-distributed-with-standard-deviation-probability?show=4001#a4001</guid>
<pubDate>Tue, 17 Apr 2012 14:30:40 +0000</pubDate>
</item>
<item>
<title>Answered: If 2.5 mol of ethylene oxide is decomposed at 93 degrees celcius what will be the final temperature of the products? The heat capacity of the products is 110.13J/mol C?</title>
<link>http://www.prepjunk.com/3998/ethylene-decomposed-temperature-products-capacity-products?show=3999#a3999</link>
<description>&lt;p&gt;In this question we must need the heat energy (q) value.&lt;br&gt;
Let me show you with an example with use of all these data.&lt;br&gt;
Step 1:&lt;br&gt;
Ethylene Oxide = 2.5 moles.&lt;br&gt;
Heat capacity (Cp) = 110.13J/mol C&lt;br&gt;
Delta T = (T2 - T1) where T1 is initial temperature (93 C) and T2 is final temperature.&lt;br&gt;
Formula : q = m x Cp x Delta T.&lt;br&gt;
Let us assume the heat energy (q) is 2753 J.&lt;br&gt;
So 2753 J = 2.5 moles x 110.13J/mol C x Delta T&lt;br&gt;
Delta T = (2753 J)/(2.5 moles x 110.13J/mol C)&lt;br&gt;
(T2 - 93 ) = 9.99 C&lt;br&gt;
Final Temperature(T2) = 9.99 +93 = 102.99 C or 103 C.&lt;/p&gt;
</description>
<category>Chemistry</category>
<guid isPermaLink="true">http://www.prepjunk.com/3998/ethylene-decomposed-temperature-products-capacity-products?show=3999#a3999</guid>
<pubDate>Tue, 17 Apr 2012 14:26:24 +0000</pubDate>
</item>
<item>
<title>Answered: What is the break-even quantity for this product? Use both graphic and algebraic approaches to get your answer.</title>
<link>http://www.prepjunk.com/3996/break-quantity-product-graphic-algebraic-approaches-answer?show=3997#a3997</link>
<description>&lt;p&gt;17500* 22=18x+80000&lt;br&gt;
x=16944.44&lt;br&gt;
b)sales increased by 30 percent&lt;br&gt;
p=17500* 22* 0.3 =115500&lt;br&gt;
c)variable cost reduced to 85%&lt;br&gt;
p=18* 16944.44* 0.15&lt;br&gt;
=45748&lt;br&gt;
sales increased by 30 percent==&amp;gt;more profit&lt;/p&gt;
</description>
<category>Chemistry</category>
<guid isPermaLink="true">http://www.prepjunk.com/3996/break-quantity-product-graphic-algebraic-approaches-answer?show=3997#a3997</guid>
<pubDate>Tue, 17 Apr 2012 10:54:33 +0000</pubDate>
</item>
<item>
<title>Answered: Why do the group 5A elements have relatively small electron affinities compared to the neighboring nonmetals in the corresponding rows?</title>
<link>http://www.prepjunk.com/3994/relatively-affinities-neighboring-nonmetals-corresponding?show=3995#a3995</link>
<description>&lt;p&gt;The group 5A elements have valence electronic configuration of ns2 np3&lt;br&gt;
=&amp;gt; the three np orbitals are all half filled with one electron each and it is a relatively stable configuration&lt;br&gt;
=&amp;gt; adding an electron to this results in a less stable situation &lt;br&gt;
=&amp;gt; electron affinity is lower &lt;/p&gt;

&lt;p&gt;For the other neighbouring nonmetals&lt;br&gt;
=&amp;gt; electronic configuration with added electron is more stable than original electronic configuration&lt;br&gt;
=&amp;gt; electron affinity is higher&lt;/p&gt;
</description>
<category>Chemistry</category>
<guid isPermaLink="true">http://www.prepjunk.com/3994/relatively-affinities-neighboring-nonmetals-corresponding?show=3995#a3995</guid>
<pubDate>Tue, 17 Apr 2012 10:52:00 +0000</pubDate>
</item>
<item>
<title>Answered: Determine the larger root of the following equation: log(a) + log(a + 16) = 2 log(a + 4).</title>
<link>http://www.prepjunk.com/3991/determine-the-larger-root-the-following-equation-log-log-log?show=3992#a3992</link>
<description>&lt;p&gt;given this,&lt;br&gt;
log(a) + log(a + 16) = 2 log(a + 4).&lt;br&gt;
log a(a+16) = log (a+4)^2&lt;br&gt;
so a(a+16) = (a+4)^2&lt;br&gt;
a^2+16a = a^2+8a+16&lt;br&gt;
8a = 16 --&amp;gt; a = 2 answer&lt;/p&gt;
</description>
<category>Electrical Engg</category>
<guid isPermaLink="true">http://www.prepjunk.com/3991/determine-the-larger-root-the-following-equation-log-log-log?show=3992#a3992</guid>
<pubDate>Mon, 16 Apr 2012 05:51:56 +0000</pubDate>
</item>
<item>
<title>Answered: What type of channel is stop and wait protocol used for?</title>
<link>http://www.prepjunk.com/3989/what-type-of-channel-is-stop-and-wait-protocol-used-for?show=3990#a3990</link>
<description>&lt;p&gt;Noiseless channels&lt;/p&gt;
</description>
<category>Electrical Engg</category>
<guid isPermaLink="true">http://www.prepjunk.com/3989/what-type-of-channel-is-stop-and-wait-protocol-used-for?show=3990#a3990</guid>
<pubDate>Mon, 16 Apr 2012 05:50:58 +0000</pubDate>
</item>
<item>
<title>Answered: According to the Nyquist bit rate doubling the bandwidth does what to the bit rate?</title>
<link>http://www.prepjunk.com/3987/according-nyquist-rate-doubling-bandwidth-does-what-the-rate?show=3988#a3988</link>
<description>&lt;p&gt;Bandwidth doubles&lt;/p&gt;
</description>
<category>Electrical Engg</category>
<guid isPermaLink="true">http://www.prepjunk.com/3987/according-nyquist-rate-doubling-bandwidth-does-what-the-rate?show=3988#a3988</guid>
<pubDate>Mon, 16 Apr 2012 05:50:04 +0000</pubDate>
</item>
<item>
<title>Answered: Compute the area of the triangle for the triangle having vertices (1,1), (-1,2), and (-2, -1).</title>
<link>http://www.prepjunk.com/3985/compute-the-area-the-triangle-triangle-having-vertices-and?show=3986#a3986</link>
<description>&lt;p&gt;a=(1,1)&lt;br&gt;
b=(-1,2)&lt;br&gt;
c= (-2, -1)&lt;br&gt;
ab=(-2,1)=(x1,y1)&lt;br&gt;
ac=(-3,-2)=(x2,y2)&lt;br&gt;
area=0.5 | x1y2-y2x1 |&lt;br&gt;
=0.5 | 4+3 |&lt;br&gt;
=3.5&lt;/p&gt;
</description>
<category>Calculus</category>
<guid isPermaLink="true">http://www.prepjunk.com/3985/compute-the-area-the-triangle-triangle-having-vertices-and?show=3986#a3986</guid>
<pubDate>Sun, 15 Apr 2012 11:51:38 +0000</pubDate>
</item>
<item>
<title>Answered: Compute the area of the triangle for the triangle having vertices (1,0,1), (0,2,3) and (-1,5,-2).</title>
<link>http://www.prepjunk.com/3983/compute-the-area-the-triangle-triangle-having-vertices-and?show=3984#a3984</link>
<description>&lt;p&gt;A=(1,0,1)&lt;br&gt;
B=(0,2,3&lt;br&gt;
C=(-1,5,-2)&lt;br&gt;
AB=(-1,2,2)&lt;br&gt;
AC=(-2,5,-3)&lt;br&gt;
AB X AC=-16i-7j-1k&lt;br&gt;
IAB X ACI=√(256+49+1)=√306&lt;/p&gt;

&lt;p&gt;AREA=0.5IAB X ACI=8.74&lt;/p&gt;
</description>
<category>Calculus</category>
<guid isPermaLink="true">http://www.prepjunk.com/3983/compute-the-area-the-triangle-triangle-having-vertices-and?show=3984#a3984</guid>
<pubDate>Sun, 15 Apr 2012 11:49:23 +0000</pubDate>
</item>
<item>
<title>Answered: Is trans-methyl cinnamate a good substitute for ethyl acetate to use as a solvent ? why or why not?</title>
<link>http://www.prepjunk.com/3979/trans-methyl-cinnamate-good-substitute-ethyl-acetate-solvent?show=3980#a3980</link>
<description>&lt;p&gt;Yes it is a good substitute of ethyl esistate to use as a solvent.&lt;br&gt;
Both have about same soluble properties but one advantage which has trans-methyl cinnamate is its ease of availability and its odor which is very sweet and most importantly it desolve easily within every liquid of same polarity. It desolve much faster than ethyl acetate due to weak bonds than ethyl acetate. So, comparing these two trans-methyl cinnamate is better but when trans-methyl cinnamate is not available than ethyl acetate can be used.&lt;/p&gt;
</description>
<category>Chemistry</category>
<guid isPermaLink="true">http://www.prepjunk.com/3979/trans-methyl-cinnamate-good-substitute-ethyl-acetate-solvent?show=3980#a3980</guid>
<pubDate>Fri, 13 Apr 2012 12:38:10 +0000</pubDate>
</item>
<item>
<title>Answered: Given the initial concentrations of 0.10 atm NO2 and 0.10 atm N2O4 in a 1.0 L flask, what will be the equilibrium partial pressure of NO2?</title>
<link>http://www.prepjunk.com/3977/initial-concentrations-flask-equilibrium-partial-pressure?show=3978#a3978</link>
<description>&lt;p&gt;N2O4&amp;gt;2NO2&lt;br&gt;
0.1-X&amp;gt;0.1+2X&lt;br&gt;
(0.1+2X)/(0.1-X)=0.66&lt;br&gt;
X=-0.012&lt;/p&gt;

&lt;p&gt;AS X IS NEGATIVE THE REACTION IS TAKING PLACE IN REVERSE DIRECTION &lt;br&gt;
2NO2&amp;gt;N2O4&lt;br&gt;
PARTIAL PRESSURE OF NO2 =0.1+2X=0.074 ATM&lt;/p&gt;
</description>
<category>Chemistry</category>
<guid isPermaLink="true">http://www.prepjunk.com/3977/initial-concentrations-flask-equilibrium-partial-pressure?show=3978#a3978</guid>
<pubDate>Fri, 13 Apr 2012 12:37:22 +0000</pubDate>
</item>
<item>
<title>Answered: the formation of ozone hole in the antratic region has been a cause of concern.what could be reason for</title>
<link>http://www.prepjunk.com/3972/formation-ozone-antratic-region-cause-concern-could-reason?show=3973#a3973</link>
<description>&lt;p&gt;Presence of prominent polar front and stratospheric’ clouds; and inflow of chlorofluorocarbons&lt;/p&gt;
</description>
<category>UPSC</category>
<guid isPermaLink="true">http://www.prepjunk.com/3972/formation-ozone-antratic-region-cause-concern-could-reason?show=3973#a3973</guid>
<pubDate>Thu, 12 Apr 2012 11:56:56 +0000</pubDate>
</item>
<item>
<title>in term of economy the visit by foreign nationals to witness the 19 commonwealth games in india amounted to</title>
<link>http://www.prepjunk.com/3971/economy-foreign-nationals-witness-commonwealth-amounted</link>
<description>
</description>
<category>UPSC</category>
<guid isPermaLink="true">http://www.prepjunk.com/3971/economy-foreign-nationals-witness-commonwealth-amounted</guid>
<pubDate>Thu, 12 Apr 2012 07:56:16 +0000</pubDate>
</item>
<item>
<title>which of carbon dioxide ,oxide of nitrogen ,oxides of sulphur are the emmission from coal combustion at thermal power plant</title>
<link>http://www.prepjunk.com/3970/carbon-dioxide-nitrogen-sulphur-emmission-combustion-thermal</link>
<description>
</description>
<category>UPSC</category>
<guid isPermaLink="true">http://www.prepjunk.com/3970/carbon-dioxide-nitrogen-sulphur-emmission-combustion-thermal</guid>
<pubDate>Thu, 12 Apr 2012 07:51:28 +0000</pubDate>
</item>
<item>
<title>which of carbon dioxide oxide of nitrogen oxides of sulphur are the emmission from coal combustion at thermal power plant</title>
<link>http://www.prepjunk.com/3969/carbon-dioxide-nitrogen-sulphur-emmission-combustion-thermal</link>
<description>
</description>
<category>UPSC</category>
<guid isPermaLink="true">http://www.prepjunk.com/3969/carbon-dioxide-nitrogen-sulphur-emmission-combustion-thermal</guid>
<pubDate>Thu, 12 Apr 2012 07:50:12 +0000</pubDate>
</item>
<item>
<title>satellite used for telecommunication are kept in a geostationary orbit a satellite</title>
<link>http://www.prepjunk.com/3967/satellite-telecommunication-geostationary-orbit-satellite</link>
<description>
</description>
<category>UPSC</category>
<guid isPermaLink="true">http://www.prepjunk.com/3967/satellite-telecommunication-geostationary-orbit-satellite</guid>
<pubDate>Thu, 12 Apr 2012 07:46:12 +0000</pubDate>
</item>
<item>
<title>in union budget 2011-12 a full exemption from the basic cistom duty was extended to the bioasphalt ? what is importance of this material</title>
<link>http://www.prepjunk.com/3966/exemption-cistom-extended-bioasphalt-importance-material</link>
<description>
</description>
<category>UPSC</category>
<guid isPermaLink="true">http://www.prepjunk.com/3966/exemption-cistom-extended-bioasphalt-importance-material</guid>
<pubDate>Thu, 12 Apr 2012 07:43:48 +0000</pubDate>
</item>
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